Zen Math Crossword

Spill Games
4.9
Ratings
100,000+
Downloads
PEGI 3
Age
16
Versions

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Download Latest APK (1.56, 196.8 MB)

About this app

NameZen Math Crossword
CategoryBoard
PriceFree
Safety100% Safe
DeveloperSpill Games
Version1.56
Packagecom.spill.math.puzzle.games.crossmath.number.free
App ID29385
Updated2026-08-18
Requires8.0
Zen Math Crossword screenshot 1Zen Math Crossword screenshot 2Zen Math Crossword screenshot 3Zen Math Crossword screenshot 4Zen Math Crossword screenshot 5Zen Math Crossword screenshot 6Zen Math Crossword screenshot 7Zen Math Crossword screenshot 8Zen Math Crossword screenshot 9Zen Math Crossword screenshot 10Zen Math Crossword screenshot 11Zen Math Crossword screenshot 12

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Zen Math Crossword is a board game from Spill Games. 94% of raters give it full marks.

Free to download, though in-app purchases run £1.79 - £89.99 if billed through Play, and it shows ads. Content is rated PEGI 3. It needs Android 8.0 or newer. 44 people have left a written review.

Rating distribution

510,568
4442
3221
20
10

Previous APK Versions All 16 ›

Frequently asked questions

01 Is Zen Math Crossword free?

Yes. Zen Math Crossword is listed as free on Google Play and offers in-app purchases (£1.79 - £89.99 if billed through Play); it also shows ads.

02 Which Android version does Zen Math Crossword need?

The current release requires Android 8.0. If your device is older, one of the 16 earlier versions listed above may still install.

03 How do I install the APK?

Download the file from the version page, open it on your Android device and allow installs from this source when prompted. XAPK bundles need the APKPure app or a split-APK installer (see the install guide in the footer). Always prefer the latest version unless you specifically need an older build.

04 Is the download safe?

Files are served by an established third-party mirror and are the same builds distributed to Play Store users; APK Rewind never repackages or modifies them. Check the developer name (Spill Games) and package name (com.spill.math.puzzle.games.crossmath.number.free) match what you expect.

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